Question

two object of different masses one of 10g and other of 100g are dropped from are dropped from the same height will they reach the ground at the same time? explain your answer​

Answer 1

$\huge \mathbb \red {ANSWER}$

$\bold{yes \: they \: will \: reach \: at \: ground \: in \: same \: time \: }$

$\large \underline \green{explantion \: }$

• so they will reach in same time coz g or gravity pulls them with same acceleration down towards the earth

there is mathamatical proof

$let \: assume \: a \: body \: mass \: m \: falling \: into \: earth \: \\\ so \: gravitational \: force \: start \: working \: between \: earth \: and \: that \: object \: of \: mass \: m \\ \\ ie \: \boxed{f = \frac{g \times m \times me}{ {r}^{2} }} (where \: g = 6.67 \times {10}^{11} m = mass \: of \: object \: and \: me = mass \: of \: earth)$

$also \:there \: must \: be \: certain \: force \: pulling \: object \: downward \: \ \\ \\ ie \: \: \boxed{f = mg} \: \: where \: (m = mass \: of \: object \: g = acceleration \: = 9.8m {s}^{ - 2} )$

$then \: we \: can \: say \: that \: mg = \frac{g \times m \times me}{ {r}^{2} }$

$coz \: force \: acting \: on \: \: object \: is \: same \:$

$on \: both \: sides \: there \: is \: m \: so \: it \: will \: get \: cancel \: out \\ \\ ie \: \boxed{g = \frac{g \times me}{ {r}^{2} } } \:$

so from above we can say that g or acceletion due to gravity does not depends upon mass of object

hope it helps you

be brainly