two object of mass 0.1 kg and 0.2 kg are moving along the same line and direction with velocity of 2m/s and 1m/s respectively they collide are after collision the first object move at a velocity of 1.67m/s determine the velocity of the second object after collision?
Answers
Answer:
1.165 m/s
Explanation:
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore, m1v1 + m2v2 = m1v3 + m2v4
On sustitututing the known and given values we get
2(0.1) + 1(0.2) = 1.67(0.1) + v4 × (0.2)
0.4 = 0.167 + 0.2 × v4
v4= 1.165 m/s
Answer
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
Answer:
1.165 m/s
Explanation:
Mass of first objects, m₁= 100 g = 0.1 kg
Mass of second object, m₂ = 200 g = 0.2 kg
Velocity of m₁ before collision, v₁= 2 m/s
Velocity of m₂ before collision, v₂ = 1 m/s
Velocity of m₁ after collision, v₃ = 1.67 m/s
Velocity of m₂ after collision = v₄
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
m₁v₁ + m₂v₂ = m₁v₃+ m₂v₄
⇒ 0.1 * 2 + 0.2 * 1 = 0.1 * 1.67 + 0.2 * v₄
⇒ 0.4 = 0.67 + 0.2 * v₄
⇒ v₄ = 1.165 m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
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