Two object of mass 5 kg and 8 kg at rest. F1 and F2 are the forces applied on the boat respectively. if the speed of both the object after 10 second become 10 metre per second and 20 metre per second then find the value of F1 - F2
Answers
Answer:
Horizontal force,F=600 N
Mass of body A, m
1
=10 kg
Mass of body B, m2=20 kg
Total mass of the system, m=m1+m2=30 kg
Using Newtons second law of motion, the acceleration (a) produced in the system can be calculated as:
F=ma
a=
m
F
=
30
600
=20m/s
2
When force F is applied on body A:
The equation of motion can be written as: F−T=m
1
a
T=F−(m
1
)a
=600−10×20=400 N (i)
When force F is applied on body B:
The equation of motion can be written as:
F−T=m
2
a
T=F−(m
2
)a
T=600−20×20=200 N (ii)
which is different from value of T in case (i). Hence our answer depends on which mass end, the force is applied.
Answer:
Given:
First Object:
Mass (m₁) = 5 kg
Initial Velocity (u₁) = 0 m/s
Final velocity (V₂) = 16 m/s
time = 5 s
We know that,
Force = mass * acceleration
And acceleration = (v - u) / t.
Hence,
F₁ = 5* (160) / 5
→ F₁ = 5 * 16/5
→ F₁ = 16 N
Second Object:
Mass (m₂) = 8 kg
Initial Velocity (U₂) = 0 m/s
Final Velocity (v₂) = 15 m/s
Time 5 s
Hence,
F₂ = 8 (15-0)/5
→ F₂=8*15/5
→ F₂ = 24 N
Additional Information:
Force:
• It is the push or pull of an Object.
• It is a vector quantity.
• It is denoted by "F".
• F = ma, where m is the Mass of the Object and a is it's acceleration.
• It's units are Newtons (N) and dynes (dyn).
• It depends on mass & acceleration of the object.