Question

two object of mass 50 gram and hundred gram are moving along the same line and direction with velocity of 5 metre per second and 10 metre per second respectively they collide and after the collision the second object moves at a velocity of 8 metre per second determine the velocity of first object​

Answer 1

Answer:

9 metre per second

Explanation:

mass of first object M1 = 50g = 0.05 kg

mass of second object M2 = 100 gram = 0.1 kg

initial velocity of first object U1=5m/s

initial velocity of second object U2=10m/s

After collision,

let final velocity of first object V1 be x

final velocity of second object V2= 8m/s

By Newton's law of conservation of momentum,

M1U1 + M2U2 = M1V1 + M2V2

=> 0.05kg*5m/s + 0.1kg*10m/s = 0.05kg*x + 0.1kg*8m/s

=>0.25kgm/s + 1kgm/s = 0.05kg*x + 0.8kgm/s

=>1.25kgm/s - 0.8kgm/s = 0.05kg*x

=>0.45kgm/s ÷ 0.05kg=x

=>45m/5s = x

=>9m/s = x

∴ After the collision, the velocity of first object will be 9m/s

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Answer 2

Answer:

hope this may help you...