Question

two object of masses100g and200g are moving along the same line and direction with velocities of2ms-1and1ms-1,respectively.​

Answer 1

Hence, the velocity of the second object becomes 1.165 m/s after the collision.

Explanation:

According to the law of conservation of momentum:

Total momentum before collision = Total momentum after collision

Therefore, m1v1 + m2v2 = m1v3 + m2v4

On sustitututing the known and given values we get

2(0.1) + 1(0.2) = 1.67(0.1) + v4 × (0.2)

0.4 = 0.167 + 0.2 × v4

v4= 1.165 m/s

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Answer 2

Explanation:

Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m/s and 1 m/s, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m/s.