Physics, asked by PradipChauhan51, 11 months ago

Two objects 2 kg and 6 kg are placed.
Where, 2 kg in left.
If 6 kg moves 2 meter towards right then by what distance does 2 kg should move that centre of mass will remain at its initial position. ​

Answers

Answered by nirman95
18

Answer:

In order to solve this type of question, let is consider the centre of mass of the 2 particle system to be located at origin (0,0)

Now, the shift should be such that the centre of mass be still at origin.

Let change in position of 2kg be ∆x1 and Chang in position of 6 kg be ∆x2.

Using the formula for centre of mass calculation:

(m1 *∆x1 + m2*∆x2)/(m1 +m2) = 0

=> 2 *∆x1 + 6*2 = 0

=> ∆x1 = -6 metres.

negative sign indicates that 2 kg has to moved to opposite direction as that of 6kg.

The answer is 6 metres to the left.

Explanation:

Answered by ram5556
8

Answer:

We using formula for centre of Calculating Mass .

(m1 × /\x1 + m2 × /\x2 )/(m1 + m2 ) = 0 .

= 2×/\x1 + 6×2 = 0 .

= /\x1 = - 6 metres .

if 2 kg is moved in the size of -6 KG so it can be 6 kg .

Answer : 6 metre to left .

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