Two objects, 4 times as massive as the other, are approaching each other under their mutual gravitational attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 1m/s2. When the separation between them is 25 km, the acceleration of the heavier object is?
Answers
Answered by
2
Answer:
if this helps u then mark me as brainliest and follow me...
Explanation:
Given,
Mass of the first body ×4=mass of the second body.
Let the acceleration of the body be a
As per law gravitation,
F=
r
2
GMm
a At r=100km, 1=
m
F
=
(100)
2
GM
=>G=1⋅
M
(100)
2
At r=25cm,
M
F
=
(25)
2
Gm
=
4
1
(
25
100
)
2
=4m/s
2
Similar questions