Question

Two objects A and B have masses in the ratio of 2:1 and are dropped from the same height
1. What is the ratio of velocities of A and B when they strike the ground
2. What is the ratio of forces of A and B when they strike the ground

Answer 1

hey dear ur answer hope it helps u

Answer 2

Using the equation of motion:  v = u + at

           For 1st body, a = g, u = 0

⇒ v₁ = 0 + gt₁    ⇒ v₁ = gt₁

           For 2nd body, a = g, u = 0

⇒ v₂ = 0 + gt₂    ⇒  v₂ = gt₂

Using, S = ut + 1/2 at²,

⇒ S₁ = 0(t) + g(t₁)²/2   ⇒ S₁ =  g(t₁)²/2

⇒ S₂ = 0(t) + g(t₂)²/2   ⇒ S₂ =  g(t₂)²/2

  But since they are dropped form same height, S₁ = S₂:

⇒ g(t₁)²/2 = g(t₂)²/2

⇒ t₁ = t₂    

Hence,  v₁ = gt₁  &  v₂ = gt₂

 v₁ = gt₁ = gt₂ = v₂       [t₁ = t₂]

(ii)   F = ma  , let masses be 2x and x

For 1st body, F₁ = 2xa

For 2nd bod, F₂ = 1xa = xa

Ratio of forces = (2xa):(xa) = 2 : 1