Question

Two objects A and B, having mass 100 kg and 75 kg, moving with velocity 40 kmh-1 and 6 kmh-1
respectively. Answer the following:
a. Which will have greater inertia?
b. Which will have greater momentum?
c. Which will stop first if equal negative acceleration is applied on both?
d. Which will travel greater distance?
e. Which will impart greater impulse if collides with a wall?

Answer 1

Answer:

Given :

Mass of first object=A=m1=100kg

speed =v1=40km/hr=40x5/18m/s

mass of second object=B=m2=75kg.

speed of seond object=v2=60km/hr=60 x5/18 m/s

1] As Inertia is a measure of mass, so object with mass 100kg will have more inertia.

2]Momentum =mass x velocityMomentum of first object=100x40x5/18=1111.1kg-m/s

Momentum of second object=75x60x5/18=1250 kg-m/s

Therefore second object has greater momentum.

3]If a negative acceleration is applied to both bodies then the body with smaller initial velocity will stop first that is First Object A.

4]From Third equation of motion -- V²-u²=2as.

Therefore body having higher velocity will travel a greater distance that is second object B.

5]The body having higher momentum will provide greater impulse during collision so answer is Object B .

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