Two objects A and B, having mass 100 kg and 75 kg, moving with velocity 40 km/hr and 6 km/hr respectively. Answer the following: a. Which will have greater momentum? b.which will stop first if equal negative acceleration is applied on both? c.which will travel greater distance?
a) p(A)> p(B) , b) object B , C) Object B
a) p(A)> p(B) , b) object B , C) Object A
a) p(A)< p(B) , b) object B , C) Object B
a) p(A)< p(B) , b) object B , C) Object A
(HINT=CHAPTER FORCE AND LAW OF MOTION)
Answers
Given :
Mass of first object=A=m1=100kg
speed =v1=40km/hr=40x5/18m/s
mass of second object=B=m2=75kg.
speed of seond object=v2=60km/hr=60 x5/18 m/s
1] As Inertia is a measure of mass, so object with mass 100kg will have more inertia.
2]Momentum =mass x velocityMomentum of first object=100x40x5/18=1111.1kg-m/s
Momentum of second object=75x60x5/18=1250 kg-m/s
Therefore second object has greater momentum.
3]If a negative acceleration is applied to both bodies then the body with smaller initial velocity will stop first that is First Object A.
4]From Third equation of motion -- V²-u²=2as.
Therefore body having higher velocity will travel a greater distance that is second object B.
5]The body having higher momentum will provide greater impulse during collision so answer is Object B ...
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