Question

Two objects A and B of masses m and 4 m are dropped simultaneously in a vacuum what is the ratio of the time taken to fall

Answer 1

Answer:

Explanation:

For a freely falling object :

a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we get h2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =b

so,

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