Two objects are dropped from a bridge, an interval of 1.0 s apart. Air resistance is negligible. During the time that both objects continue to fall, their separation
Answers
Two objects are dropped from a bridge, an interval of 1.0 s apart. Air resistance is negligible. During the time that both objects continue to fall, their separation
A) increases.
B) decreases.
C) stays constant.
D) increases at first, but then stays constant.
E) decreases at first, but then stays constant.
answer : option (A) increases
explanation : let first object at t = 0, initial velocity, u = 0,
after time t , distance covered by 1st ball, s1 = 1/2gt² [ as g is acceleration due to gravity. ]
2nd ball is dropped just 1 s after 1st ball, so distance covered by second ball, s2 = 1/2 g(t - 1)²
separation between them, s1 - s2 = 1/2 gt² - 1/2g(t - 1)²
= 1/2 g[t² - t² + 2t - 1] = 1/2 g(2t - 1)
we see separation ∝ (2t - 1)
it means separation increases with respect to time. therefore option (A) is correct choice.
Answer:
If the two objects are dropped at 1.0 s time interval, their velocity will increase as they descend which will cause their separation distance to increase because velocity is directly proportional to displacement.
The rate at which each object falls is influenced by their respective weights. If air resistance is negligible, gravity will continue to pull each object until it hits the ground.
The influence of gravity will cause the following:
The speed of each object will increase gradually until it hits the ground, and each object will have maximum velocity before it hits the ground.
• This shows that velocity of each object
increases as it descends.
Velocity is directly proportional to displacement, as the velocity of each object increases, the distance between them will also increase.Thus, if the two objects are dropped at 1.0 s time interval, their velocity will increase as they descend which will cause their separation distance to increase because velocity is directly proportional to displacement.