)Two objects are located on the same side of a tower. Their
angles of depression as observed from the top of the tower are
45° and 60°. Find the distance between two objects if the height
of the tower is 200 metres
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84.53m
Step-by-step explanation:
if you'll make the figure, you'll see two triangles with a common side, which would be the tower.
the bigger triangle would be an isosceles triangle as it have two angles equal which would be 45°. Hence the distance of the object having angle of depression as 45 will be equal to the length of the tower which will be 200m.
now with the help of Tan 60, you'll get the distance of the object which is at 60° angle of depression from the tower which will be around 115.47m.
Hence the distance between the objects = 200-115.47 = 84.53m
Sorry as I could not upload the figure or it would be more clear through it !
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