Question

Two objects are thrown up at angles of 45 and 60 respectively,with horizontal. Such that maximum height attained by them is same. The ratio of velocity of projection is

Answer 1

h=v1sin^2A/2g = v2sin^2B/2g

v1=sin^2 45° v2=sin^2 60°

v1/v2=under root 3/2

Answer 2

Answer:

h=v1sin^2A/2g = v2sin^2B/2g

v1=sin^2 45° v2=sin^2 60°

v1/v2=under root 3/2