two objects are thrown up at angles of 45 and 60 respectively with the horizontal if both object again same vertical Heights in the ratio of magnitude of velocity with which these are projected is
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Maximum height can be given by H = u² sin²θ/ 2g
∵ H is same ⇒ u1 / u2 = sinθ2 / sinθ1.................
Shraddhapatnaik:
yaa..its correct
but can u give it's solution..
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