Question

Two objects are thrown vertically upwards simultaneously with velocities x and y respectively. Prove that:

a) The height reached by them would be in the ratio of x²:y².
b) The time taken to reach the maximum height would be in the ratio of xy.​

Answer 1

Answer:

solved

Explanation:

max height reached = u²/2g = u²/20

time taken to reach the maximum height  = u/g = u/10

a) The height reached by them would be in the ratio of x²/20 : y²/20 = x² : y²

b) The time taken to reach the maximum height would be in the ratio of

x/10 : y/10 = x : y

Answer 2

you can follow the solution in picture given.

Thanks for the question Hope the solution helps!

Have a nice day :)