Question

Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after collision?

Answer 1

Explanation:

HEY MATE .......

$given : \\ \\ m1 = m2 = 1.5 |kg| \\ \\ u1 = 2.5m {s}^{ - 1} \\ \\ u2 = 2.5m {s}^{ - 1} \\ \\ total \: mass \: of \: the \: combined \: \\ system \\ \\ m = m1 + m2 = 2 \times 1.5 = 3kg \\ \\ let \: the \: velocity \: of \: \\ \\ the \: combined \:system \: \\ \\ after \: \: the \: collision \: be \: (v) \\ \\ after \: applying \: \\ \\ conservation \: of \: momentum \: \\ \\ before \: and \: after \: the \: collision : \\ \\ m1 \: u1 - m2 \: u2 = mv \\ \\ 1.5 \times 2.5 - 1.5 \times 2.5 = 3v \\ \\ \implies \: v = 0$

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Answer 2

0m/s

Explanation:

According to conservation of linear momentum

M1u1+ M2u2 = V(M1 + M2)

1.5*2.5 + 1.5 * (-2.5)= V(1.5+1.5)

0 = 3V

V = 0 m/s