Question

Two objects, each of mass 1.5 kg, are moving in the same
straight line but in opposite directions. The velocity of each
object is 2.5 m s-1 before the collision during which they
stick together. What will be the velocity of the combined
object after collision?

Answer 1

Concept:

• during collision the Momentum will remain conserved due to zero external forces.
• since its inelastic collision, both stick together after collision, both will have same final velocity and will move together.

Solution:

1. mass of objects = m = 1.5kg
2. initial velocity of objects = u= 2.5m/s
3. combined final velocity = v = ?

Let's name them as A and B

Momentum conservation

$\longrightarrow \rm \vec{P}_{initial} = \vec{P}_{final}$

$\longrightarrow \rm mu( \hat{i} )+ mu(\hat{-i} )= (m+m)v$

$\longrightarrow \rm mu \hat{i} - mu\hat{i} = 2mv$

$\longrightarrow \rm 0 = 2mv$

$\longrightarrow \bf v = 0 \:ms^{‐1}$

That means, the both objects will come at rest after collision.

All energy they possesed initially, get lost during collision.

Answer 2

Explanation:

$\huge\mathcal\colorbox{lavender}{{\color{b}{✿Yøur-Añswer♡}}}$

$\large\bf{\underline{\red{VERIFIED✔}}}$

Concept:

• during collision the Momentum will remain conserved due to zero external forces.
• since its inelastic collision, both stick together after collision, both will have same final velocity and will move together.

Solution:

mass of objects = m = 1.5kg

initial velocity of objects = u= 2.5m/s

combined final velocity = v = ?

Let's name them as A and B

Momentum conservation

$\longrightarrow \rm \vec{P}_{initial} = \vec{P}_{final}$

$\longrightarrow \rm mu( \hat{i} )+ mu(\hat{-i} )= (m+m)v$

$\longrightarrow \rm mu \hat{i} - mu\hat{i} = 2mv$

$\longrightarrow \rm 0 = 2mv$

$\longrightarrow \bf v = 0 \:ms^{‐1}$

That means, the both objects will come at rest after collision.

All energy they possesed initially, get lost during collision.

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${\sf{\bf{\blue{@Muskanjoshi14࿐}}}}$