Question

Two objects each of mass 2 kg, are moving in the same straight line but in
opposite directions. The velocity of each object is 1.5 ms before the collision
during which they stick together. What will be the velocity of the combined object
after collision?​

Answer 1

Answer:

Given :-

Mass of both object = 2 kg

Velocity of Object 1 = 1.5 m/s

Velocity of Object 2 = -1.5 m/s

To Find :-

The velocity of the combined object after collision?

SoluTion :-

Firstly let's find Mounmentum of both object

Object (1)

Mounmentum = Mass × Velocity

Mounmentum = 2 × 1.5

Mounmentum = 3 kg m/s

Object (2)

Mounmentum = Mass × Velocity

Mounmentum = 2 × -1.5

Mounmentum = -3 kg m/s

Total Mounmentum before collision = 3 + (-3)

Total Mounmentum before Collision = 0

Total Mass = Mass of Object 1 + Mass of Object 2

Total mass = 2 + 2 = 4 kg

Now,

Total Mounmentum after collision = (Mass1 + Mass 2) × v

Total Mounmentum after Collision = (2 + 2) × v

Total Mounmentum after Collision = 4 × v = 4v

Now,

Total Mounmentum before Collision = Total Mounmentum after Collision

0 = 4 × v

0/4 = v

0 = v

Hence :-

$\mathfrak \red{ \checkmark \: velocity \: is \: 0 \: }$

Answer 2

Answer:

$hello$

Mass of one of the objects, m1 = 1.5 kg

Mass of the other object, m2 = 1.5 kg

Velocity of m1 before collision, u1 = 2.5 m/s

Velocity of m2, moving in opposite direction before collision, u2 = ˆ’2.5 m/s

Let v be the velocity of the combined object after collision. By the law of conservation of momentum,

Total momentum after collision = Total momentum before collision,

Or, (m1 + m2) v = m1u1 + m2u2

Or, (1.5 + 1.5) v = 1.5 — 2.5 +1.5 — (€“2.5) [negative sign as moving in opposite direction] Or, v = 0 ms€“1