Question

Two objects having equal masses are moving with uniform velocities of 3 m/s and 7m/s respectively. Calculate the ratio of their kinetic energies.
i need the correct answer

Answer 1

Answer:

Find The Kinetic Energy of First body

K1= 1/2 m(3)²=9m

The Kinetic energy of Second body

K2=1/2m(7)²=49m

m[ Here m1=m2=m ]

Now Ratio of Kinetic energies = 9m : 49m

Ratio of their Kinetic energies is 9:49

Answer 2

$\Huge{\underline{\underline{\red{\sf{Answer :}}}}}$

$\large \tt \: Given\begin{cases} \sf{Mass \: of \: 2 \: objects \: are \: same } \\ \sf{Velocity \: of \: masses \: are \: 3m/s \: and \: 7 \: m/s} \end{cases}$

Solution :

$\tt {\Large{formula}} \: for \: kinetic \: energy \: is \:$

$\Large \longrightarrow \displaystyle {\underline{\boxed{\sf{K.E \: = \: \frac{1}{2} \: mv^2}}}}$

As mass is same so take it as m.

Now put values of v

Ratio

$\Large \rightarrow \displaystyle {\sf{\frac{K.E_{1}}{K.E_{2}} \: = \: \frac{ \cancel{\frac{1}{2}} \cancel{m} ({3})^{2} }{ \cancel{\frac{1}{2}} \cancel{m} ({7})^{2} } }}$

$\Large \rightarrow {\sf{Ratio \: = \: \frac{(3)^2}{(7)^2}}}$

$\Large \rightarrow {\sf{Ratio \: = \: \frac{9}{49}}}$

$\huge{\sf{ Ratio \: = \: 9:49}}$

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