Question

Two objects move with initial velocity -9.15 m/s, final velocity 18.3 m/s, and constant accelerations.The first object has displacement 19.5 m. What is its acceleration? The second object travels a total distance of 22.5 m. What is its acceleration?

Answer 1

Answer:

Acceleration of first object is given by, a1 = 6.44 m/s^2

Explanation:

Let u = initial velocity = -9.15 m/s

Let v = final velocity = 18.3 m/s

Let s1 = displacement of first object = 19.5 m

Let a1 = acceleration of first object

a1 = (v^2 - u^2) / (2 x s1)

a1 = [(18.3 m.s)^2 - (-9.15 m/s)^2] / (2 x 19.5 m)

a1 = 6.44 m/s^2