Question

Two objects of equal masses are moving with velocities and 2v. Compare their
Kinetic energies​

Answer 1

K.E=0.5×m× $v^{2}$                                                                                             K.E(1st)=0.5×m×$v^{2}$                                                                                                          K.E(2nd)=0.5×m×(2$v)^{2}$  

Hence the ratio is 0.5×m×$v^{2}$: 0.5×m×($2v)^{2}$ $= 1:4$

Hence the ratio is 1:4.

Answer 2

Answer:

thanks for giving points