Question

Two objects of mass 100g and 200g are moving along the same line and in same direction with velocities 2m/s and 1m/s. They collide and stick together. The loss of kinetic energy of 100g mass is

Answer 1

helo bro

mass of 1st body M1=100 g
mass of 2nd body M2=200 g
velocity of body 1 = 2 m/s
velocity of 2nd body = 1 m/s

as final momentum becomes zero
both the objects have zero velocity

now change in velocity of 100 g body is 2-0 =2
Change in Kinetic Energy = 1/2×0.1×2^2

0.2 Joules


thanks

Answer 2

Answer:

The loss of kinetic energy of 100 g mass is 0.112 J.

Explanation:

Given that,

Mass $m_{1}=100\ g$

Mass $m_{2}=200\ g$

Velocity $u_{1}=2\ m/s$

Velocity $u_{2}=1\ m/s$

We know that,

The kinetic energy of 100 g is

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times0.1\times(2)^2$

$K.E= 0.2\ J$

Using equation of conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v$

$0.1\times2+0.2\times1=(0.1+0.2)v$

$v = \dfrac{0.2+0.2}{0.1+0.2}$

$v= 1.33\ m/s$

The kinetic energy for 100 g

$K.E=\dfrac{1}{2}mv^2$

$K.E=\dfrac{1}{2}\times0.1\times(1.33)^2$

$K.E= 0.088445\ J$

The loss of kinetic energy of 100 g mass is

$K.E= 0.2-0.088445$

$K.E= 0.112\ J$

Hence, The loss of kinetic energy of 100 g mass is 0.112 J.