Question

two objects of massea 100 g and 200 g are moving along the same line and direction with velocity of 2m s^1 and 1 m s^1 respectively​

Answer 1

Answer:

Before Collision After collision

A B A B

• 100 g 200g → 100g 200g
• 2m/s 1m/s v=? 1.67ms
• −1

Let the 100 g and 200 g objects be A and B as shown in above figure.

• Initial momentum of A=
• 1000
• 100

• ×2=0.2kgms
• −1

Initial momentum of B=

• 1000
• 200

• ×1=0.2kgms
• −1

∴ Total momentum of A and B before collision

• =0.2+0.2=0.4kgms
• −1

Let the velocity of A after collision =v

∴ Momentum of A after collision =

• 1000
• 100

×v=0.1v

• Also, momentum of B after collision
• =
• 1000
• 200

×1.67=0.334kgms

−1

∴ Total momentum of A and B after collision

=0.1×v+0.334

• Using the law of conservation of momentum, momentum of A and B after collision = momentum of A and B before collision
• 0.1×v+0.334=0.4
• 0.1×v=0.4−0.334
• ⇒v=
• 0.1
• 0.066

0.66ms ^-1