Question

Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m/s and 1 m/s respectively. They collide and after collision, the first object moves at a velocity of 1.67 m/s. Determine the velocity of 2nd object.​

Answer 1

$\huge\bold\purple{Bonjour!!}$

$\huge\mathfrak{Solution:-}$

⏩ **Here,

* m1 = 100g = 0.1 kg.

*m2= 200g= 0.2 kg.

**Given :-

*u1= 2 m/s,

*u2 = 1 m/s,

*v1= 1.67 m/s.

** To find:-

*v2..

Ans. According to the law of conservation of momentum,

m1u1 + m2u2 = m1v1 + m2v2

Now, on substituting the values, we get,

0.1 × 2 + 0.2 × 1 = 0.1 × 1.67 + 0.2 × v2

=> 0.2 + 0.2 = 0.167 + 0.2 × v2

=> v2 = 1.165 m/s. [The velocity of the second object].

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Answer 2

$\huge{\boxed{\boxed{\textsf{\purple{ANSWER}}}}}$

By conservation of linear momentum →

$m_1u_1 \: + m_2u_2 = \: m_1v_1 + m_2v_2 \\ \\ 0.1 \times 2 + 0.2 \times 1 = 0.1 \times 1.67 + 0.2 \times v_2 \\ \\ 0.2 + 0.2 = 0.167 + 0.2v_2 \\ \\ 0.4 - 0.167 = 0.2v_2 \\ \\ v_2 = 1.165 m s^{-1}$

Thanks ! ❤️❤️