Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2 m s−1 and 1 m s−1, respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m s−1. Determine the velocity of the second object.
Answers
Mass of one of the objects, m1 = 100 g = 0.1 kg
Mass of the other object, m2 = 200 g = 0.2 kg
Velocity of m1 before collision, v1=2 m/s
Velocity of m2 before collision, v2=1 m/s
Velocity of m1 after collision,v3=1.67m/s
Velocity of m2 after collision = v4
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore m1v1 + m2v2 = m3v3 + m4v4
(0.1)2 + (0.2)1 = (0.1)1.67 + (0.2)v4
0.4 = 0.167 + 0.2v4
Therefore v4 = 1.165m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
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Answer:
1.165 m/s
Explanation:
Mass of one of the objects, m1 = 100 g = 0.1 kg
Mass of the other object, m2 = 200 g = 0.2 kg
Velocity of m1 before collision, v1 = 2 m/s
Velocity of m2 before collision, v2 = 1 m/s
Velocity of m1 after collision, v3 = 1.67 m/s
Velocity of m2 after collision = v4
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
m1v1 + m2v2 = m3v3 + m4v4
(0.1) x 2 + (0.2) x 1 = (0.1) x 1.67 + (0.2) x v4
0.4 = 0.167 + 0.2v4
v4 = 1.165 m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision.