Two objects of masses 100 g and 200 g are moving along the same line and direction with velocities of 2ms- and 1ms-l, respectively. the collide and after the collision the first abject moves at a velocity of 1.67 m s-1 determine the velocity of the second object
Answers
Explanation:
Let the first object and second object be A and B respectively.
We have,
Mass of A = 100g or 0.1 kg
Mass of B = 200g or 0.2 kg
Initial Velocity of A = 2m/s
Initial Velocity of B = 1 m/s
Momentum = Mass x Velocity
Therefore initial momentum of A = 0.1 x 2 = 0.2 kg m/s
Initial momentum of B = 0.2 x 1 =
0.2 kg m/s
Final velocity of A = 1.67 m/s
Therefore final momentum of A = 0.1 x 1.67 = 0.167 kg m/s
We have to find the final velocity of B.
Let final velocity of B = v
Therefore final momentum of B = 0.2v
We can use the law of conservation of momentum to find the solution of this problem.
By this law,
Initial momentum of the particle = Final momentum of the particle.
Therefore
Initial momenta of A and B = Finial momenta of A and B
0.2 + 0.2 = 0.167 + 0.2v
v = (0.2 + 0.2 - 0.167) / 0.2
v = 1.165 m/s
Answer:
1.165m/s
Explanation:
From Law Of Conservation of Momentum for two rigid Bodies :
m1u1 + m2u2 = m1v1 + m2v2
Thus by substituting the given values in the above eqn.
we get
100(2) + 200 (1) = 100(1.67) + 200(v2)
where v2 is the final velocity of the 2nd object after collision
200(v2) = 100 { 2 - 1.67 } + 200(1)
2v2 = 1 {0.33} + 2
v2 = 2.33/2
v2 = 1.165m/s