Two objects of masses 100 g and, 200 g are moving along the same line and direction with velocities of 2 m/s and 1 m/s respectively.
Answers
Answered by
1
Explanation:
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore, m1v1 + m2v2 = m1v3 + m2v4
On sustitututing the known and given values we get
2(0.1) + 1(0.2) = 1.67(0.1) + v4 × (0.2)
0.4 = 0.167 + 0.2 × v4
v4= 1.165 m/s
Answer
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
Answered by
1
Answer:
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore, m1v1 + m2v2 = m1v3 + m2v4
On sustitututing the known and given values we get
2(0.1) + 1(0.2) = 1.67(0.1) + v4 × (0.2)
0.4 = 0.167 + 0.2 × v4
v4= 1.165 m/s
Answer
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
Similar questions