Two objects of masses 100 g and 200 g are moving along the same
line and direction with velocities of 2 m/ s and 1 m /s, respectively.
They collide and after the collision, the first object moves at a velocity
of 1.67 m /s. Determine the velocity of the second object.
Answers
Answer:
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We can solve the given problem by using the law of conservation of momentum.
Given
Mass of one of the objects (m₁) = 100 g = 0.1 kg Mass of the other object (m₂) = 200 g = 0.2 kg Velocity of m₁ after collision (v3) = 1.67 m/s
Velocity of m₁ before collision (v₁) = 2 m/s Velocity of m2 before collision (v₂) = 1 m/s
Find out
Velocity of m2 after collision=V4
Solution
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore, m₁v₁ + m₂V₂ = ₁V3 + m₂V4
On sustitututing the known and given values we get
2(0.1) +1(0.2) = 1.67(0.1) + v4× (0.2)
0.4 0.167 + 0.2 × V4 V4= 1.165 m/s
Answer
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
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