Science, asked by Chopdekarpranvi, 5 months ago

Two objects of masses 100g & 200g are moving along the same line & direction with velocities of 2m5-1 & 1ms-1 ; respectively they collide & after the collision, the first object moves at a velocity of 1.67m5-1 , Determine the velocity of the second object​

Answers

Answered by Ekaro
11

Given :

Two objects of masses 100g and 200g are moving along the same direction with velocities of 2m/s and 1m/s.

After collision first object moves at a velocity of 1.67 m/s.

To Find :

Velocity of second object after collision.

Solution :

❒ Since no net force acts on the system, linear momentum of whole system is conserved.

  • We know that momentum is measured as the product of mass and velocity.
  • It is a vector quantity having both magnitude as well as direction.
  • SI unit : N s

★ Initial momentum of system :

➛ m₁u₁ + m₂u₂

➛ (100)(2) + (200)(1)

➛ 200 + 200

400 N s

★ Final momentum of system :

➛ m₁v₁ + m₂v₂

➛ (100)(1.67) + 200v₂

167 + 200v₂

Initial momentum of system is equal to the final momentum of system.

➠ 400 = 167 + 200v₂

➠ 200v₂ = 400 - 167

➠ 200v₂ = 233

➠ v₂ = 233/200

v₂ = 1.16 m/s

Answered by SarcasticAngel
15

Answer:

Given :

Two objects of masses 100g and 200g are moving along the same direction with velocities of 2m/s and 1m/s.

After collision first object moves at a velocity of 1.67 m/s.

To Find :

Velocity of second object after collision.

Solution :

❒ Since no net force acts on the system, linear momentum of whole system is conserved.

We know that momentum is measured as the product of mass and velocity.

It is a vector quantity having both magnitude as well as direction..

SI unit : N s

★ Initial momentum of system :

➛ m₁u₁ + m₂u₂

➛ (100)(2) + (200)(1)

➛ 200 + 200

➛ 400 N s

★ Final momentum of system :

➛ m₁v₁ + m₂v₂

➛ (100)(1.67) + 200v₂

➛ 167 + 200v₂

Initial momentum of system is equal to the final momentum of system.

➠ 400 = 167 + 200v₂

➠ 200v₂ = 400 - 167

➠ 200v₂ = 233

➠ v₂ = 233/200

➠ v₂ = 1.16 m/s

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