Question

Two objects of masses 100g and 200g are moving along the same line and direction with velocities of 2 m/s and 1m/s respectively they collide and after the collision the first object moves at a velocity of 1.67m/s determine the velocity of the second object

Answer 1

By law of conservation of momentum

M1v1+m2 v2=miv3+m2v4

100*2+200*1=100*1.67+200*v4

400-167/200=1.665

Answer 2

Explanation:

By the conservation of momentum

Let the first object be O1 and the second object be O2

Before collision

Mo1=m1u1    

After collision  

Mo1=m1v1                            

Fab= rate of change of momentum

F1AB = m1*(v1-u1)/t

F2AB = m2*(v2-u2)/t

as per the 3rd law of the motion

Fab/F1 = -Fba/F2

F1 =F2

m1*(v1-u1)/t = m2*(v2-u2)/t

by cutting t from both the equation and multiplying in both equation  

m1v1-m1u1=m2v2-m2u2

V2=m1v1-m1u1+m2u2/m2

V2=100*1.67-100*200+200*1/200

V2= 167-200+200/200

=167/200

=0.835 m/s

by doing roundoff

=0.84 m/s

hope it helps you

please mark it as a brainliest answer