Two objects of masses 10kg and 20kg are falling from heights 20m and 10m find the ratio of their times to reach ground
Answers
Answer:
as we know
h1/m1=h2/m2
put values
20/10=10/20
2=1/2
Explanation:
I think its will support for you
Given : Two objects of masses 10kg and 20kg are falling from heights 20m and 10m
To find : the ratio of their times to reach ground
Solution:
S = ut + (1/2)at²
objects of masses 10kg falling from heights 20m
u = 0 falling
t = ?
a = g
S = 20
=> 20 = 0 + (1/2)gt²
=> t² = 40/g
=> t = √40/g
objects of masses 20kg falling from heights 10m
u = 0 falling
t = ?
a = g
S = 10
=> 10 = 0 + (1/2)gt²
=> t² = 20/g
=> t = √20/g
Ratio of time =
Ratio : √40/g : √20/g
= √2 : 1
ratio of their times to reach ground = √2 : 1
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