Question

Two objects of masses 20 kg and 60 kg are kept 4 m apart. The gravitational force between them
*F' N. If a third object of 5 kg mass is placed at mid point between them, the per gravitational of
5 kg mass due to former two objects will be​

Answer 1

Answer:

i dont know

Explanation:

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Answer 2

Answer:

C.$\frac{4}{3}F$

Explanation:

We are given that

Mass of one object $m_1=20 kg$

$m_2=60 kg$

$m_3=5kg$

Distance between $m_1$ and $m_2$=4 m

Distance between $m_1$ and $m_3=2 m$

Distance between $m_2$ and $m_3=2 m$

We know that gravitational force =$\frac{GmM}{r^2}$

Gravitational force between $m_1\;and\;m_2=F=\frac{G(20)(60)}{4^2}=75 G$

Gravitational force between $m_1\;and\;m_3=\frac{G(20)(5)}{2^2}=25G$

Gravitational force between $m_2\;and\;m_3=\frac{G(5)(60)}{2^2}=75G$

Net gravitational force on $m_3=25G+75G=100G$

$\frac{net\;gravitational\;force \;on\;m_3}{F}=\frac{100G}{75G}=\frac{4}{3}$

Net gravitational force on $m_3=\frac{4}{3}F$

Answer:C.$\frac{4}{3}F$