Two objects of masses 20 kg and 60 kg are kept 4 m apart. The gravitational force between them is 'F' N. If a third object of 5 kg mass is placed at mid point between them, the net gravitational force on 5 kg mass due to former two objects will be
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Answer:
The answer will be 375 N
Explanation:
According to the problem the mass of both the particles are 20 kg and 60 kg respectively
The gravitational force is mentioned as F Newton
Now the the mid object is placed at the point of 2 m
Therefore the gravitational force for mass 20 kg
f1 = -GmM/r^2 = 10 x 5 x 20 /4 = 250 N
Therefore the gravitational force for mass 10 kg
f2 = -GmM/r^2 = 10 x 5 x 10/4 = 125 N
Therefore the net force acting on the middle body is 250 +125 N or 375N
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