Two objects of masses 20 kg and 60 kg are kept 4 m apart. The gravitational force between them is 'F' N. If a third object of 5 kg mass is placed at mid point between them, the net gravitational force on 5 kg mass due to former two objects will be
(A)3/2F
(B)2/3F
(C)4/3F
(D)3/4F
Answers
Answered by
0
Answer:
3/2f
Explanation:
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Answered by
1
Answer:
2/3F
Explanation:
F(20,60) = G* 20 * 60/ (4*4) = f (assumed)
F(20,5) = G* 20 * 5/ (2*2) = f*(4/12) = f/3
multiplied by 4 due to distance and divided by 12 due to mass
F(60,5) = G* 5 * 60/ (2*2) = f*(4/4) = f
effective force = 2/3f (because both objects will apply force in different direction )
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