Question

Two objects of masses 20 kg and 60 kg are kept 4 m apart. The gravitational force between them is 'F' N. If a third object of 5 kg mass is placed at mid point between them, the net gravitational force on 5 kg mass due to former two objects will be

(A)3/2F

(B)2/3F

(C)4/3F

(D)3/4F

Answer 1

Answer:

3/2f

Explanation:

Big In the morning to you tomorrow

Answer 2

Answer:

2/3F

Explanation:

F(20,60) = G* 20 * 60/ (4*4) = f (assumed)

F(20,5) = G* 20 * 5/ (2*2) = f*(4/12) = f/3

multiplied by 4 due to distance and divided by 12 due to mass

F(60,5) = G* 5 * 60/ (2*2) = f*(4/4) = f

effective force = 2/3f (because both objects will apply force in different direction )