Question

Two objects of
masses 200 g and 300 g are moving along the same line and direction with velocities of 3 m/s
and 4 m/s respectively. They collide and after the collision the first object moves at a velocity
of 1.53 m/s. Determine the velocity of the second object. please answer it fast

Answer 1

Answer:4.98m/s

Explanation:

According to law of conservation of energy

M1u1+M2u2= M1v1 +M2v2

200*3 + 300*4 = 200*1.53 + 300*v

600+1200=306+300v

1800-6=300+300v

1794/300= 1+v

V+1= 5.98

V=4.98 ans

Hope it helps

Answer 2

Answer :- 4.98m/s

Step by step explanation :-

Mass of the first object, m¹ = 200g = 0.2kg

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/s

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/s

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/s

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ?

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ? Total momentum before collision,

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ? Total momentum before collision, P¹ = (m¹u¹) +(m²u²)

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ? Total momentum before collision, P¹ = (m¹u¹) +(m²u²) = (0.2kg×3m/s) + (0.3kg×4m/s)

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ? Total momentum before collision, P¹ = (m¹u¹) +(m²u²) = (0.2kg×3m/s) + (0.3kg×4m/s) = 0.6kgm/s + 1.2kgm/s

Mass of the first object, m¹ = 200g = 0.2kgMass of the second object, m² = 300g = 0.3kg Initial velocity of the first object, u¹ = 3m/sInitial velocity of the second object = 4m/sFinal velocity of the first object, v¹ = 1.53m/sFinal velocity of the second object, v² = ? Total momentum before collision, P¹ = (m¹u¹) +(m²u²) = (0.2kg×3m/s) + (0.3kg×4m/s) = 0.6kgm/s + 1.2kgm/s = 1.8kgm/s

Total momentum After collision,

P² = (m¹v¹) + (m²v²)

= (0.2kg×1.53m/s) + (0.3kg×v²)

= 0.306kgm/s + 0.3v²

Acording to the law of conservation of momentum,

(m¹u¹) + (m²u²) = (m¹v¹) + (m²v²)

1.8kgm/s = 0.306kgm/s + 0.3v²

1.8kgm/s - 0.306kgm/s = 0.3v²

1.494kgm/s = 0.3v²

(1.494kgm/s) / (0.3kg) = v²

4.98m/s = v²

Therefore, the velocity of the second object is 4.98m/s after the collision.

I hope it will help you