Question

Two objects of masses hundred gram and 200 gram and moving along the same line and direction with velocities of 2 metre per second then 1 metre per second respectively they collide and after the collision the first object moves at the velocity of 1.67 metre per second determine the velocity of the second object

Answer 1

Answer:

putting m1v1 - m2v2 = m1u1 - m2u2 we get

200 g = 0.2 kg

100 g = 0.1kg

0.1(2) - 0.2(1) = 0.1(1.67) - 0.2(x)

0 = 0.167 - 0.2x

x = 0.167/0.2

x = 0.835 m/s

Answer 2

Answer:

1.165 m/s

Explanation:

we know:

initially

m1 = 100g = 0.1kg

m2 = 200g = 0.2kg

v1 = 2 m/s

v2 = 1 m/s

finally

v1' = 1.67 m/s

find

v2'

Solution

we can use conservation of momentum, which states that initial momentum of an isolated system is always equal to the final momentum of the system.

so,

m1v1 + m2v2 = m1v1' + m2v2'

0.1*2 + 0.2*1 = 0.1*1.67 + 0.2*x. (*x is v2')

0.2 + 0.2 = 0.167 + 0.2*x

0.4 - 0.167 = 0.2*x

0.233 = 0.2*x

x = 0.233/0.2

x=233/200

x=1165/1000

x= 1.165 m/s