Question

two objects of masses m1 & m2 when separated by a distance d1 exerts a force F on each other. what is the effect on this force if

1.the masses of both the objects are doubled?
2.the distance between objects is halved?
3.how G is different from g?

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Answer 1

$\Large\bold{\underline{\underline{Answer:-}}}$

Gravitational Force is given by :

$\bf\bold{F=\frac{Gm1. m2}{d_1^2}}$

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• Masses are doubled

The force between masses only depend on the mass of the objects

Then m1'➛2m1, m2'➛2m2

So, F' = 4F

Force is changed to 4 times

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• Distance between the two bodies is reduced to half

Then d1'➛d1/2

$\bf\bold{F'=\frac{Gm1. m2}{(d_1/2)^2}}$

So F' = 4F

Force is changed to 4 times

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• G→It is define as the force of attraction acting between two bodies each of unit mass, whose centers are placed unit distance apart.
• g→It is define as the constant acceleration produced in a body when it falls freely under the effect of gravity .

F' = F because gravitational force(or G) does not depend on the medium.

Answer 2

Explanation:

1. F = (G*m1*m2)/(d^2)

where G is gravitational constant , m1 and m2

are the masses and d is the distance between them

if the masses are doubled then the force

will be four times as

F= { G*(2m1)*(2m2) }/ d^2

=4(G* m1*m2)/ d^2

thus the answer is 4 times.

2.If the distance between the objects is doubled then the fotce become one -fourth of the real force

F is inversely proportional to the square of distance between them

so, if the distance is doubled then the force becomes one - fourth of the real force.

3. There is two types of concept .

The G is large value of acceleration and g is the small value

The other concept is that G is the constant and g is the value of earth's acceleration