Question

two objects of masses m1 and m2 fall from Heights h1 and h2 respectively. the ratio of the magnitude of their momenta when they hit the ground

Answer 1

Solution: We know, h1 = ½ gt1^2 and h2 = ½ gt2^2.

We also know that velocity for body of m1 = gt1. Similarly, V2 = gt2.

The required ratio will be V1/V2 = t1/t2.

One equating the values of h1 and h2, the required ratio of this will be (h1/h2)^1/2.

Answer 2

Answer:

Correct answer is: √(h1/h2)

Explanation:

Masses m1 and m2 are immaterial to the solution of this particular problem. Here a simple explanation:

 

h1=(1/2)gt12

h2=(1/2)gt22

V1=gt1

v2=gt2

V1/V2 = t1/t2 = √(h1/h2)

 

Hope this will help.