Question

Two objects of masses m₁ and m₂ fall from the heights h₁ and h₂ respectively. Th e ratio of the magnitude of their momenta when they hit the ground is

Answer 1

when an object falls from some height on earth surface, before striking the Earth's surface , body has only kinetic energy which is gained by losing of potential energy.
I mean in case of free falling body ,
Kinetic energy at the bottom = potential energy at the top.

We know, one more important thing,
e.g., K.E = P²/2m , here P is momentum and m is mass of body
Now, For 1st body , K.E₁ = P₁²/2m₁
for 2nd body , K.E₂ = P₂²/2m₂

Potential energy of m₁ , P.E₁ = m₁gh₁
potential energy of m₂, P.E₂ = m₂gh₂
∵P.E = K.E [ from above explanation ]
so, m₁gh₁ = P₁²/2m₁ and m₂gh₂ = P₂²/2m₂
so, P₁²/P₂² = m₁²h₁/m₂²h₂
Now, taking square root both sides,
P₁/P₂ = m₁/m₂√(h₁/h₂)

Hence, option (c) is correct

Answer 2

Answer:

c) m₁/m₂√(h₁/h₂) this is answer for this question