Two objects of masses m1 and m2 when separated by a distance ‘d’ in air, attract each other with a force of 4 N. How will the magnitude of the force change, when the masses of both the objects are reduced to half?
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Answer:
According to Sir Newton's gravitational law the magnitude of gravitational force F between objects of mass m1 and m2 separated by a distance R is given by ,
now if the distance between them is doubled i.e. 2R ,then the gravitational force will be ,
now by using eq1 ,
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Gravitational Force is given by :
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Masses are doubled
The force between masses only depend on the mass of the objects
Then m1'➛2m1, m2'➛2m2
So, F' = 4F
Force is changed to 4 times
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Distance between the two bodies is reduced to half
Then d1'➛d1/2
So F' = 4F
Force is changed to 4 times
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G→It is define as the force of attraction acting between two bodies each of unit mass, whose centers are placed unit distance apart.
g→It is define as the constant acceleration produced in a body when it falls freely under the effect of gravity .
F' = F because gravitational force(or G) does not depend on the medium.
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