Question

Two objects of masses m1 and m2 when separated by a distance ‘d’ in air, attract each other with a force of 4 N. How will the magnitude of the force change, when the masses of both the objects are reduced to half?

Answer 1

Answer:

According to Sir Newton's gravitational law the magnitude of gravitational force F between objects of mass m1 and m2 separated by a distance R is given by ,

$F=G×m1×m2/R2</p><p> ............eq1 ,$

now if the distance between them is doubled i.e. 2R ,then the gravitational force will be ,

$F ′ =Gm1m2/4r²$

now by using eq1 ,

$F ′=F/4$

Answer 2

$\blue{\Large\bold{\underline{\underline{Answer:-}}} </p><p>}$

Gravitational Force is given by :

$\green{\bf\bold{F=\frac{Gm1. m2}{d_1^2}}}$

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Masses are doubled

The force between masses only depend on the mass of the objects

Then m1'➛2m1, m2'➛2m2

So, F' = 4F

Force is changed to 4 times

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Distance between the two bodies is reduced to half

Then d1'➛d1/2

$\bf\bold{F'=\frac{Gm1. m2}{(d_1/2)^2}}$

So F' = 4F

Force is changed to 4 times

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G→It is define as the force of attraction acting between two bodies each of unit mass, whose centers are placed unit distance apart.

g→It is define as the constant acceleration produced in a body when it falls freely under the effect of gravity .

F' = F because gravitational force(or G) does not depend on the medium.