Question

Two objects of masses mi and me when separated by a distance d' in air, attract each other
with a force of 4 N. How will the magnitude of the force change, when the masses of both
the objects are reduced to half?
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Answer 1

Answer:

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Explanation:

According to Sir Newton's gravitational law the magnitude of gravitational force F between objects of mass m

1

and m

2

separated by a distance R is given by ,

F=G

R

2

m

1

m

2

............eq1 ,

now if the distance between them is doubled i.e. 2R ,then the gravitational force will be ,

F

′

=G

(2R)

2

m

1

m

2

=G

4R

2

m

1

m

2

,

now by using eq1 ,

F

′

=F/4