Two objects of the mass 100g and 200g are moving at a speed of 3m/s and 4 m/s respectively undergoes collision. After collision the first object speed comes to 1.5 m/s. Find the velocity of second object after collision.
Answers
Answer:
Mass of one of the objects, m1 = 100 g = 0.1 kg
Mass of the other object, m2 = 200 g = 0.2 kg
Velocity of m1 before collision, v1= 2 m/s
Velocity of m2 before collision, v2= 1 m/s
Velocity of m1 after collision, v3= 1.67 m/s
Velocity of m2 after collision= v4
According to the law of conservation of momentum:
Total momentum before collision = Total momentum after collision
Therefore, m1v1 + m2v2 = m1v3 + m2v4
2(0.1) + 1(0.2) = 1.67(0.1) + v4(0.2)
0.4 = 0.167 + 0.2v4
v4= 1.165 m/s
Hence, the velocity of the second object becomes 1.165 m/s after the collision.
4.75 m/s is the required answer.
GIVEN:
- Mass of first object, m = 100 g = 0.1 kg
- Mass of second object, M = 200 g = 0.2 kg
- Initial velocity of first object, u = 3 m/s
- Initial velocity of second object, U = 4 m/s
- Final velocity of first object, v = 1.5 m/s
TO FIND:
Final velocity of second object ,V
FORMULA:
According to law of conservation of linear momentum,
mu+ MU = mv + MV
SOLUTION:
mu+ MU = mv + MV
(0.1×3) + (0.2×4) = (0.1×1.5) + (0.2×V)
0.3 + 0.8 = 0.15 + (0.2×V)
1.1 = 0.15 + (0.2×V)
1.1 - 0.15 = 0.2 V
0.95 = 0.2 V
V = 0.95/0.2
V = 9.5/2
V = 4.75 m/s
ANSWER:
Velocity of second object after collision is 4.75 m/s
LAW OF CONSERVATION OF LINEAR MOMENTUM:
- It is a fundamental law of nature.
- Law of conservation of linear momentum states that in the absence of external force acting on the body, total momentum before collision is equal to the total momentum after collision.
- The momentum of individual particle may change but the total momentum remains constant.