Question

Two objects, one 4 times as massive as the other, are approaching each other under their mutual gravitational attraction. When the separation between the objects is 100 km, the acceleration of the lighter object is 2 m/s2. When the separation between them is 50 km, the acceleration of the heavier object in ms-2 is m/​

Answer 1

Answer:

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Explanation:

Given,

Mass of the first body ×4=mass of the second body.

Let the acceleration of the body be a

As per law gravitation,

F=

r

2

GMm

a At r=100km, 1=

m

F

=

(100)

2

GM

=>G=1⋅

M

(100)

2

At r=25cm,

M

F

=

(25)

2

Gm

=

4

1

(

25

100

)

2

=4m/s

2