Question

two objects P and q are placed on different positions in front of a Concave mirror and produces image of same size. the size of object p is 3 times the size of object q. consider if object p is placed at 30 cm in front of mirror find the position of object q​

Answer 1

Explanation:

Size of object P is 3 times the size of object q, still the images of P and q are of equal size when placed in front of a concave mirror.

So,

size of object q be, $h_q$

then the size of object P, $h_p=3h_q$

position of the object P, $o_p=30\ cm$

Size of their images is equal means, $i_p=i_q$

Now the height of the image of the object P:

$\frac{h'_p}{h_p} =\frac{i_p}{o_p}$

where:

$h_p'=$ size of the image P

$h_p=$ size of the object P

$i_p=$ position of the image P

$\frac{h'_p}{3h_q} =\frac{i_p}{30}$ ..............................................(1)

Now the height of the image of the object q:

$\frac{h'_q}{h_q} =\frac{i_q}{o_q}$

where:

$h_q'=$ size of the image q

$h_q=$ size of the object q

$i_q=$ position of the image q

$\frac{h'_q}{h_q} =\frac{i_q}{o_q}$

$o_q=\frac{h_q}{h_q'}\times i_q$

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TOPIC: magnification by concave lens

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