Two objects P and Q have masses in the ratio of 3:1 and are dropped from
the same height
(0) What is the ratio of velocities of P and Q when they strike the
ground?
What is the ratio of the forces exerted by P and Q when they strike
the ground
Answers
Answered by
0
Answer:
let the downward velocity be V
1
and upward velocity be V
2
now V
1
=
2gh
1
=
2×9.8×2
=
4×9.8
=2
9.8
momentum before collision = mV
1
= 100×10
−3
×2
9.8
=0.626
s
kgm
after collision V
2
=
2gh
2
=
2×9.8×1.5
=
3×9.8
momentum after collision = −mV
2
=−100×10
−3
3×9.8
= −0.542
s
kgm
direction is reverse therefore negative sign assigned
△P=P
f
−P
i
= -0.542-0.626 = -1.168
F=
△t
△P
=1.168×10
8
N
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