Math, asked by drewsmith33543, 5 months ago

Two ocean beaches are being affected by erosion. The table shows the width, in feet, of each beach measured at high tide where 1995 is represented by year 0: Year number Western Beach width (in feet) Dunes Beach width (in feet) 0 100 20 5 90 45 10 80 70 11 78 75 12 76 80 15 70 95 Describe the patterns shown by the erosion data measurements shown for each of the beaches in the table. Between which years will the beaches have approximately the same width? Assuming these rates remain constant, what can you do to get a better approximation of when the two beaches will have the same width?

Answers

Answered by TH3808
7

Answer:

A= 1.142 m/hr

Step-by-step explanation:

Width of beach at 8 p.m. = 36 m

Width of beach at 3 a.m. = (36-8) m =28 m

Average change in width(A) = change in width (Width of beach at 8 p.m.-Width of beach at 3 a.m.0/ time in hours

A= ( 36-28)/ 7

A= 8/7 m/hr

A = 1.142 m /hr

Thanks

Answered by ChitranjanMahajan
1

Average change in width of the beach is 1.142 m/hr

Given,

Two ocean beaches are being affected by erosion. The table shows the width, in feet, of each beach measured at high tide where 1995 is represented by year 0: Year number Western Beach width (in feet) Dunes Beach width (in feet) 0 100 20 5 90 45 10 80 70 11 78 75 12 76 80 15 70 95 Describe the patterns shown by the erosion data measurements shown for each of the beaches in the table.

To find,

Between which years will the beaches have approximately the same width? Assuming these rates remain constant, what can you do to get a better approximation of when the two beaches will have the same width?

Solution,

Width of beach at 8 p.m. = 36 m

Width of beach at 3 a.m. = (36-8) m =28 m

Average change in width(A) = change in width (Width of beach at 8 p.m.-Width of beach at 3 a.m.0/ time in hours

A= ( 36-28)/ 7

A= 8/7 m/hr

A = 1.142 m /hr

#SPJ3

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