Question

Two of the cylinders in an eight-cylinder car are defective and need to be replaced. if two cylinders are selected at random, what is the probability that
a. both defective cylinders are selected?
b. no defective cylinder is selected?
c. at least one defective cylinder is selected?

Answer 1

a 2/8
b 0/8
c 2/8
may be this is helpful to you

Answer 2

Given:

Two of the cylinders in an eight-cylinder car are defective.

To Find:

probability that

a. both defective cylinders are selected?

b. no defective cylinder is selected?

c. at least one defective cylinder is selected?

Solution:

1) Probability means likelihood of an event happening. Higher the probability, the more likely to happen. Probability is a number or fraction between 0 and 1 and in percentage 0 to 100%. A probability of 1 means something will always happen, and a probability of 0 means something will never happen.

2) P(E) = Number of the favorable outcomes / total number of the outcomes.

3) Total number of the outcome is 8.

   Defective cylinder = 2

  non defective cylinder = 6

   a) Both defective

      P(E) = Defective cylinder /  total number of outcomes

             = 2/8

       P(E)= 1/4

   b) No defective

       P(E) = Non defective / total number of outcomes

              = 6/8

       P(E) = 3/4

   c) At least one defective means that they can be two but not less than one.

      P(E) = favorable outcome / total number of the outcomes

             = 2/8×6/8 + 2/8

             = 3/16 + 1/4

       P(E)= 7/16