Question

Two open pipes of lengths 65cm and 70cm respectively, are sounded simultaneously.

How many beats per second will be produced between the fundamental frequencies

of the two pipes (velocity of sound = 330 m/s)
​

Answer 1

$hope \: this \: helps \: you$

Answer 2

Concept

The lowest frequency of a periodic waveform is known as the fundamental frequency, sometimes known as just the fundamental. The musical pitch of a note that is heard as the lowest partial existent in music is referred to as the fundamental.

Given

Two open pipes of lengths 65cm and 70cm respectively, are sounded simultaneously is given

Find

We have to find how many beats per second will be produced between the fundamental frequencies of the two pipes

Solution

The steps are as follow:.

• Let,

v = 330 m/s

L = 65 cm

l = 70 cm

Fundamental frequency = S₂ - S₁

Fundamental frequency = v / (2*length)

Fundamental frequency = $v(\frac{1}{2L}*\frac{1}{2l} )$

Fundamental frequency = $330(\frac{1}{(2*65)}*\frac{1}{(2*70)} )$

Fundamental frequency = 0.18133 x 100 Hz

Hence 0.18133 x 100 Hz  will be produced between the fundamental frequencies of the two pipes

#SPJ2