Question

two opposit angle of a parallelogtam are (3x-2) and (50-x) find the measure of each angle of parallogram​

Answer 1

hey mate!

here is ur answer.

given, 2 opp. angles of paraleelogram are (3x-2) and (50-x).

We know that , opp.sides of parallelogram are parallel as well sd equal.

so...

3x-2=50-X

3x+x=50+2

4x=52

x=52/4

x=13.

so, angles of PARALLELOGRAM are 3x-2=37degrees

and 50-x=37degrees

the remaining two angles are 180-37=143degree.

: . , the angles are 37 , 143, 37 , 143 RESPECTIVELY.

hope it helps u mate!!!

@jiya

Answer 2

Step-by-step explanation:

Let   the //gm be ABCD .

Suppose given opposite angles are angleA and angleC.

Let angleA=(3x-2)   and angleC=(50-x)  .

Since angleA and angleB lie on the same side of AB ,

therefore angleA +angleB=180 degrees ,

that is (3x-2)+angleB=180    

similarly angleC+angleD=180 degrees .                    

that is   (50-x)+angleD=180                                        

THEREFORE  (3x-2)+angleB=(50-x)+angleD            

that is   angleB-angleD=(50-x)-(3x-2)=50-x-3x+2 =52-4x.  

AGAIN angleA and angleD lie on the same side of AD

, therefore angleA+angleD=180degrees,

which means (3x-2)+angleD=180  

ALSO angleB and angleC lie on the same side of BC  therefore angleB+angleC=180degrees :

that is  angleB+(50-x)=180      

NOW (3x-2)+angleD=angleB+(50-x)    

 that is angleB-angleD=(3x-2)-(50-x)=3x-2-50+x =4x-52  

THUS we have angleB-angleD=52-4x =4x-52 HENCE

 52-4x=4x-52  that is 104=8x              

OR  8x=104  

OR x=104/8 =13 when x=13  

THEN angleA=(3x-2)=39-2=37 degrees,

angleC=(50-x)=50-13=37degrees,

angleB=180-37=143degrees

,angleD=180-37=143degrees.          

 NOTE it is better to draw the diagram of//gm ABCD to understand the above solution,